Integrand size = 24, antiderivative size = 65 \[ \int \sqrt {2+e x} \left (12-3 e^2 x^2\right )^{3/2} \, dx=-\frac {96 \sqrt {3} (2-e x)^{5/2}}{5 e}+\frac {48 \sqrt {3} (2-e x)^{7/2}}{7 e}-\frac {2 (2-e x)^{9/2}}{\sqrt {3} e} \]
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Time = 0.01 (sec) , antiderivative size = 65, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {641, 45} \[ \int \sqrt {2+e x} \left (12-3 e^2 x^2\right )^{3/2} \, dx=-\frac {2 (2-e x)^{9/2}}{\sqrt {3} e}+\frac {48 \sqrt {3} (2-e x)^{7/2}}{7 e}-\frac {96 \sqrt {3} (2-e x)^{5/2}}{5 e} \]
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Rule 45
Rule 641
Rubi steps \begin{align*} \text {integral}& = \int (6-3 e x)^{3/2} (2+e x)^2 \, dx \\ & = \int \left (16 (6-3 e x)^{3/2}-\frac {8}{3} (6-3 e x)^{5/2}+\frac {1}{9} (6-3 e x)^{7/2}\right ) \, dx \\ & = -\frac {96 \sqrt {3} (2-e x)^{5/2}}{5 e}+\frac {48 \sqrt {3} (2-e x)^{7/2}}{7 e}-\frac {2 (2-e x)^{9/2}}{\sqrt {3} e} \\ \end{align*}
Time = 0.32 (sec) , antiderivative size = 52, normalized size of antiderivative = 0.80 \[ \int \sqrt {2+e x} \left (12-3 e^2 x^2\right )^{3/2} \, dx=-\frac {2 (-2+e x)^2 \sqrt {4-e^2 x^2} \left (428+220 e x+35 e^2 x^2\right )}{35 e \sqrt {6+3 e x}} \]
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Time = 2.18 (sec) , antiderivative size = 44, normalized size of antiderivative = 0.68
method | result | size |
gosper | \(\frac {2 \left (e x -2\right ) \left (35 x^{2} e^{2}+220 e x +428\right ) \left (-3 x^{2} e^{2}+12\right )^{\frac {3}{2}}}{315 e \left (e x +2\right )^{\frac {3}{2}}}\) | \(44\) |
default | \(-\frac {2 \sqrt {-3 x^{2} e^{2}+12}\, \left (e x -2\right )^{2} \left (35 x^{2} e^{2}+220 e x +428\right )}{105 \sqrt {e x +2}\, e}\) | \(46\) |
risch | \(\frac {2 \sqrt {\frac {-3 x^{2} e^{2}+12}{e x +2}}\, \sqrt {e x +2}\, \left (35 e^{4} x^{4}+80 e^{3} x^{3}-312 x^{2} e^{2}-832 e x +1712\right ) \left (e x -2\right )}{35 \sqrt {-3 x^{2} e^{2}+12}\, e \sqrt {-3 e x +6}}\) | \(88\) |
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none
Time = 0.64 (sec) , antiderivative size = 62, normalized size of antiderivative = 0.95 \[ \int \sqrt {2+e x} \left (12-3 e^2 x^2\right )^{3/2} \, dx=-\frac {2 \, {\left (35 \, e^{4} x^{4} + 80 \, e^{3} x^{3} - 312 \, e^{2} x^{2} - 832 \, e x + 1712\right )} \sqrt {-3 \, e^{2} x^{2} + 12} \sqrt {e x + 2}}{105 \, {\left (e^{2} x + 2 \, e\right )}} \]
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\[ \int \sqrt {2+e x} \left (12-3 e^2 x^2\right )^{3/2} \, dx=3 \sqrt {3} \left (\int 4 \sqrt {e x + 2} \sqrt {- e^{2} x^{2} + 4}\, dx + \int \left (- e^{2} x^{2} \sqrt {e x + 2} \sqrt {- e^{2} x^{2} + 4}\right )\, dx\right ) \]
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Result contains complex when optimal does not.
Time = 0.28 (sec) , antiderivative size = 71, normalized size of antiderivative = 1.09 \[ \int \sqrt {2+e x} \left (12-3 e^2 x^2\right )^{3/2} \, dx=\frac {2 \, {\left (-35 i \, \sqrt {3} e^{4} x^{4} - 80 i \, \sqrt {3} e^{3} x^{3} + 312 i \, \sqrt {3} e^{2} x^{2} + 832 i \, \sqrt {3} e x - 1712 i \, \sqrt {3}\right )} {\left (e x + 2\right )} \sqrt {e x - 2}}{105 \, {\left (e^{2} x + 2 \, e\right )}} \]
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Exception generated. \[ \int \sqrt {2+e x} \left (12-3 e^2 x^2\right )^{3/2} \, dx=\text {Exception raised: TypeError} \]
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Time = 0.18 (sec) , antiderivative size = 71, normalized size of antiderivative = 1.09 \[ \int \sqrt {2+e x} \left (12-3 e^2 x^2\right )^{3/2} \, dx=\frac {2\,\sqrt {12-3\,e^2\,x^2}\,\sqrt {e\,x+2}\,\left (-35\,e^3\,x^3-10\,e^2\,x^2+332\,e\,x+168\right )}{105\,e}-\frac {4096\,\sqrt {12-3\,e^2\,x^2}}{105\,e\,\sqrt {e\,x+2}} \]
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